Base | Representation |
---|---|
bin | 100001111010000101100… |
… | …011101100011101010001 |
3 | 22020202102120200211201112 |
4 | 201322011203230131101 |
5 | 301134032412020142 |
6 | 4542234504143105 |
7 | 330226241501204 |
oct | 41720543543521 |
9 | 8222376624645 |
10 | 2330113001297 |
11 | 819217052714 |
12 | 317712167a95 |
13 | 13b961ca1533 |
14 | 80ac705393b |
15 | 40929187382 |
hex | 21e858ec751 |
2330113001297 has 2 divisors, whose sum is σ = 2330113001298. Its totient is φ = 2330113001296.
The previous prime is 2330113001273. The next prime is 2330113001329. The reversal of 2330113001297 is 7921003110332.
It is an a-pointer prime, because the next prime (2330113001329) can be obtained adding 2330113001297 to its sum of digits (32).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1852146796096 + 477966205201 = 1360936^2 + 691351^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2330113001297 is a prime.
It is not a weakly prime, because it can be changed into another prime (2330113001497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1165056500648 + 1165056500649.
It is an arithmetic number, because the mean of its divisors is an integer number (1165056500649).
Almost surely, 22330113001297 is an apocalyptic number.
It is an amenable number.
2330113001297 is a deficient number, since it is larger than the sum of its proper divisors (1).
2330113001297 is an equidigital number, since it uses as much as digits as its factorization.
2330113001297 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 32.
The spelling of 2330113001297 in words is "two trillion, three hundred thirty billion, one hundred thirteen million, one thousand, two hundred ninety-seven".
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