Base | Representation |
---|---|
bin | 1010100110100000000011… |
… | …01101111110101100110001 |
3 | 10001112201012210220112022121 |
4 | 11103100001231332230301 |
5 | 11023430222444010301 |
6 | 121325521231434241 |
7 | 4624213426360303 |
oct | 523200155765461 |
9 | 101481183815277 |
10 | 23313111313201 |
11 | 7479042623746 |
12 | 27462a1985981 |
13 | 10015560b9218 |
14 | 5a8509719973 |
15 | 2a6662d773a1 |
hex | 153401b7eb31 |
23313111313201 has 2 divisors, whose sum is σ = 23313111313202. Its totient is φ = 23313111313200.
The previous prime is 23313111313067. The next prime is 23313111313243. The reversal of 23313111313201 is 10231311131332.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23219917877025 + 93193436176 = 4818705^2 + 305276^2 .
It is a cyclic number.
It is not a de Polignac number, because 23313111313201 - 211 = 23313111311153 is a prime.
It is not a weakly prime, because it can be changed into another prime (23313111413201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11656555656600 + 11656555656601.
It is an arithmetic number, because the mean of its divisors is an integer number (11656555656601).
Almost surely, 223313111313201 is an apocalyptic number.
It is an amenable number.
23313111313201 is a deficient number, since it is larger than the sum of its proper divisors (1).
23313111313201 is an equidigital number, since it uses as much as digits as its factorization.
23313111313201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 23313111313201 its reverse (10231311131332), we get a palindrome (33544422444533).
The spelling of 23313111313201 in words is "twenty-three trillion, three hundred thirteen billion, one hundred eleven million, three hundred thirteen thousand, two hundred one".
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