Base | Representation |
---|---|
bin | 1010100110100000011011… |
… | …01100110011100101111111 |
3 | 10001112201201211011100111012 |
4 | 11103100031230303211333 |
5 | 11023431130424112114 |
6 | 121325553212145435 |
7 | 4624221420120353 |
oct | 523201554634577 |
9 | 101481654140435 |
10 | 23313312332159 |
11 | 7479136042213 |
12 | 274633916827b |
13 | 100158893c255 |
14 | 5a85282c5463 |
15 | 2a667583363e |
hex | 15340db3397f |
23313312332159 has 2 divisors, whose sum is σ = 23313312332160. Its totient is φ = 23313312332158.
The previous prime is 23313312332147. The next prime is 23313312332161. The reversal of 23313312332159 is 95123321331332.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23313312332159 - 232 = 23309017364863 is a prime.
Together with 23313312332161, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23313312332129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11656656166079 + 11656656166080.
It is an arithmetic number, because the mean of its divisors is an integer number (11656656166080).
Almost surely, 223313312332159 is an apocalyptic number.
23313312332159 is a deficient number, since it is larger than the sum of its proper divisors (1).
23313312332159 is an equidigital number, since it uses as much as digits as its factorization.
23313312332159 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 262440, while the sum is 41.
The spelling of 23313312332159 in words is "twenty-three trillion, three hundred thirteen billion, three hundred twelve million, three hundred thirty-two thousand, one hundred fifty-nine".
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