Search a number
-
+
233135403341 is a prime number
BaseRepresentation
bin1101100100011111110…
…0111111000101001101
3211021202121101120200012
43121013330333011031
512304430130401331
6255033444443005
722562212142321
oct3310774770515
9737677346605
10233135403341
118a965948165
12392246a9465
1318ca5156809
14b3d8adb981
1560e748b82b
hex3647f3f14d

233135403341 has 2 divisors, whose sum is σ = 233135403342. Its totient is φ = 233135403340.

The previous prime is 233135403337. The next prime is 233135403349. The reversal of 233135403341 is 143304531332.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 138046430116 + 95088973225 = 371546^2 + 308365^2 .

It is a cyclic number.

It is not a de Polignac number, because 233135403341 - 22 = 233135403337 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 233135403298 and 233135403307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (233135403349) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116567701670 + 116567701671.

It is an arithmetic number, because the mean of its divisors is an integer number (116567701671).

Almost surely, 2233135403341 is an apocalyptic number.

It is an amenable number.

233135403341 is a deficient number, since it is larger than the sum of its proper divisors (1).

233135403341 is an equidigital number, since it uses as much as digits as its factorization.

233135403341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38880, while the sum is 32.

Adding to 233135403341 its reverse (143304531332), we get a palindrome (376439934673).

The spelling of 233135403341 in words is "two hundred thirty-three billion, one hundred thirty-five million, four hundred three thousand, three hundred forty-one".