Base | Representation |
---|---|
bin | 1101100100101111100… |
… | …0011001111001100011 |
3 | 211021221012102001102212 |
4 | 3121023320121321203 |
5 | 12310044013430311 |
6 | 255044201232335 |
7 | 22563642304022 |
oct | 3311370317143 |
9 | 737835361385 |
10 | 233201311331 |
11 | 8a99a07387a |
12 | 392427926ab |
13 | 18cb59c1921 |
14 | b4037768b9 |
15 | 60ed159c8b |
hex | 364be19e63 |
233201311331 has 2 divisors, whose sum is σ = 233201311332. Its totient is φ = 233201311330.
The previous prime is 233201311319. The next prime is 233201311333. The reversal of 233201311331 is 133113102332.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 233201311331 - 26 = 233201311267 is a prime.
It is a super-2 number, since 2×2332013113312 (a number of 24 digits) contains 22 as substring.
Together with 233201311333, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 233201311297 and 233201311306.
It is not a weakly prime, because it can be changed into another prime (233201311333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116600655665 + 116600655666.
It is an arithmetic number, because the mean of its divisors is an integer number (116600655666).
Almost surely, 2233201311331 is an apocalyptic number.
233201311331 is a deficient number, since it is larger than the sum of its proper divisors (1).
233201311331 is an equidigital number, since it uses as much as digits as its factorization.
233201311331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 233201311331 its reverse (133113102332), we get a palindrome (366314413663).
The spelling of 233201311331 in words is "two hundred thirty-three billion, two hundred one million, three hundred eleven thousand, three hundred thirty-one".
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