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233242055041981 is a prime number
BaseRepresentation
bin110101000010000111100101…
…110101100110001110111101
31010120211201111211212021010111
4311002013211311212032331
5221032414212042320411
62144021530523510021
7100062116362125016
oct6502074565461675
91116751454767114
10233242055041981
1168355444510817
12221aba58388311
13a01b8292a90cb
144184d9345c00d
151be7263b4e721
hexd421e5d663bd

233242055041981 has 2 divisors, whose sum is σ = 233242055041982. Its totient is φ = 233242055041980.

The previous prime is 233242055041979. The next prime is 233242055042069. The reversal of 233242055041981 is 189140550242332.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130931035100100 + 102311019941881 = 11442510^2 + 10114891^2 .

It is a cyclic number.

It is not a de Polignac number, because 233242055041981 - 21 = 233242055041979 is a prime.

It is a super-2 number, since 2×2332420550419812 (a number of 30 digits) contains 22 as substring.

Together with 233242055041979, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (233242055041951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116621027520990 + 116621027520991.

It is an arithmetic number, because the mean of its divisors is an integer number (116621027520991).

Almost surely, 2233242055041981 is an apocalyptic number.

It is an amenable number.

233242055041981 is a deficient number, since it is larger than the sum of its proper divisors (1).

233242055041981 is an equidigital number, since it uses as much as digits as its factorization.

233242055041981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2073600, while the sum is 49.

The spelling of 233242055041981 in words is "two hundred thirty-three trillion, two hundred forty-two billion, fifty-five million, forty-one thousand, nine hundred eighty-one".