Base | Representation |
---|---|
bin | 10101101110110001… |
… | …001111110011101001 |
3 | 2020020010121101222121 |
4 | 111232301033303221 |
5 | 340241302140131 |
6 | 14415200151241 |
7 | 1454135160616 |
oct | 255661176351 |
9 | 66203541877 |
10 | 23333240041 |
11 | 9994007661 |
12 | 4632308521 |
13 | 227b127917 |
14 | 11b4c7550d |
15 | 9186d7911 |
hex | 56ec4fce9 |
23333240041 has 2 divisors, whose sum is σ = 23333240042. Its totient is φ = 23333240040.
The previous prime is 23333240039. The next prime is 23333240087. The reversal of 23333240041 is 14004233332.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 22689095641 + 644144400 = 150629^2 + 25380^2 .
It is a cyclic number.
It is not a de Polignac number, because 23333240041 - 21 = 23333240039 is a prime.
Together with 23333240039, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 23333239988 and 23333240015.
It is not a weakly prime, because it can be changed into another prime (23333240341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11666620020 + 11666620021.
It is an arithmetic number, because the mean of its divisors is an integer number (11666620021).
Almost surely, 223333240041 is an apocalyptic number.
It is an amenable number.
23333240041 is a deficient number, since it is larger than the sum of its proper divisors (1).
23333240041 is an equidigital number, since it uses as much as digits as its factorization.
23333240041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 23333240041 its reverse (14004233332), we get a palindrome (37337473373).
The spelling of 23333240041 in words is "twenty-three billion, three hundred thirty-three million, two hundred forty thousand, forty-one".
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