Base | Representation |
---|---|
bin | 1010100111010010101110… |
… | …01000000100100010010111 |
3 | 10001122022102121121012210111 |
4 | 11103221113020010202113 |
5 | 11024401430342114431 |
6 | 121350220420103451 |
7 | 4626165511513333 |
oct | 523512710044227 |
9 | 101568377535714 |
10 | 23340314019991 |
11 | 7489631868a01 |
12 | 274b613b34b87 |
13 | 1003c9ca91127 |
14 | 5a996a4467c3 |
15 | 2a72060ed7b1 |
hex | 153a57204897 |
23340314019991 has 2 divisors, whose sum is σ = 23340314019992. Its totient is φ = 23340314019990.
The previous prime is 23340314019989. The next prime is 23340314020099. The reversal of 23340314019991 is 19991041304332.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23340314019991 - 21 = 23340314019989 is a prime.
Together with 23340314019989, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23340314019901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11670157009995 + 11670157009996.
It is an arithmetic number, because the mean of its divisors is an integer number (11670157009996).
Almost surely, 223340314019991 is an apocalyptic number.
23340314019991 is a deficient number, since it is larger than the sum of its proper divisors (1).
23340314019991 is an equidigital number, since it uses as much as digits as its factorization.
23340314019991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 629856, while the sum is 49.
The spelling of 23340314019991 in words is "twenty-three trillion, three hundred forty billion, three hundred fourteen million, nineteen thousand, nine hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •