Base | Representation |
---|---|
bin | 10101101111010111… |
… | …101010110110101101 |
3 | 2020020211120010112021 |
4 | 111233113222312231 |
5 | 340301341443201 |
6 | 14420200110141 |
7 | 1454316611041 |
oct | 255727526655 |
9 | 66224503467 |
10 | 23343312301 |
11 | 9999767041 |
12 | 4635765351 |
13 | 228024333a |
14 | 11b6338021 |
15 | 919526ea1 |
hex | 56f5eadad |
23343312301 has 2 divisors, whose sum is σ = 23343312302. Its totient is φ = 23343312300.
The previous prime is 23343312281. The next prime is 23343312371. The reversal of 23343312301 is 10321334332.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12381012900 + 10962299401 = 111270^2 + 104701^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23343312301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23343312371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11671656150 + 11671656151.
It is an arithmetic number, because the mean of its divisors is an integer number (11671656151).
Almost surely, 223343312301 is an apocalyptic number.
It is an amenable number.
23343312301 is a deficient number, since it is larger than the sum of its proper divisors (1).
23343312301 is an equidigital number, since it uses as much as digits as its factorization.
23343312301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 23343312301 its reverse (10321334332), we get a palindrome (33664646633).
The spelling of 23343312301 in words is "twenty-three billion, three hundred forty-three million, three hundred twelve thousand, three hundred one".
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