Base | Representation |
---|---|
bin | 100001111110000110100… |
… | …000110110101101111111 |
3 | 22021011120000121100010021 |
4 | 201332012200312231333 |
5 | 301221400021021112 |
6 | 4544230343553011 |
7 | 330441126420511 |
oct | 41760640665577 |
9 | 8234500540107 |
10 | 2334424001407 |
11 | 820029543923 |
12 | 318515a5b767 |
13 | 13c19b172884 |
14 | 80db5801bb1 |
15 | 40acc890907 |
hex | 21f86836b7f |
2334424001407 has 2 divisors, whose sum is σ = 2334424001408. Its totient is φ = 2334424001406.
The previous prime is 2334424001389. The next prime is 2334424001431. The reversal of 2334424001407 is 7041004244332.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2334424001407 - 231 = 2332276517759 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2334424001477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1167212000703 + 1167212000704.
It is an arithmetic number, because the mean of its divisors is an integer number (1167212000704).
Almost surely, 22334424001407 is an apocalyptic number.
2334424001407 is a deficient number, since it is larger than the sum of its proper divisors (1).
2334424001407 is an equidigital number, since it uses as much as digits as its factorization.
2334424001407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64512, while the sum is 34.
Adding to 2334424001407 its reverse (7041004244332), we get a palindrome (9375428245739).
The spelling of 2334424001407 in words is "two trillion, three hundred thirty-four billion, four hundred twenty-four million, one thousand, four hundred seven".
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