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2340131301050 = 25246802626021
BaseRepresentation
bin100010000011011010101…
…100011110011010111010
322021201021202220012101112
4202003122230132122322
5301320042103113200
64551012543120322
7331032430601204
oct42033254363272
98251252805345
102340131301050
11822498126594
123196492a30a2
1313c89a6c825a
14813977bb774
1540d1395c535
hex220dab1e6ba

2340131301050 has 12 divisors (see below), whose sum is σ = 4352644220046. Its totient is φ = 936052520400.

The previous prime is 2340131301043. The next prime is 2340131301083. The reversal of 2340131301050 is 501031310432.

2340131301050 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 3 ways, for example, as 1909584043129 + 430547257921 = 1381877^2 + 656161^2 .

It is a super-2 number, since 2×23401313010502 (a number of 26 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 23401312961 + ... + 23401313060.

Almost surely, 22340131301050 is an apocalyptic number.

2340131301050 is a deficient number, since it is larger than the sum of its proper divisors (2012512918996).

2340131301050 is a wasteful number, since it uses less digits than its factorization.

2340131301050 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46802626033 (or 46802626028 counting only the distinct ones).

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 2340131301050 its reverse (501031310432), we get a palindrome (2841162611482).

The spelling of 2340131301050 in words is "two trillion, three hundred forty billion, one hundred thirty-one million, three hundred one thousand, fifty".

Divisors: 1 2 5 10 25 50 46802626021 93605252042 234013130105 468026260210 1170065650525 2340131301050