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23401452003133 is a prime number
BaseRepresentation
bin1010101001000100100110…
…01110111101111100111101
310001212011020102111112221111
411110202103032331330331
511031402133203100013
6121434251215202021
74633461540012211
oct524422316757475
9101764212445844
1023401452003133
1175025556435a6
12275b436b16311
13100999420a809
145ac8ca0c4941
152a8ad36db73d
hex1548933bdf3d

23401452003133 has 2 divisors, whose sum is σ = 23401452003134. Its totient is φ = 23401452003132.

The previous prime is 23401452003119. The next prime is 23401452003143. The reversal of 23401452003133 is 33130025410432.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19359313606084 + 4042138397049 = 4399922^2 + 2010507^2 .

It is a cyclic number.

It is not a de Polignac number, because 23401452003133 - 25 = 23401452003101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 23401452003095 and 23401452003104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23401452003103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11700726001566 + 11700726001567.

It is an arithmetic number, because the mean of its divisors is an integer number (11700726001567).

Almost surely, 223401452003133 is an apocalyptic number.

It is an amenable number.

23401452003133 is a deficient number, since it is larger than the sum of its proper divisors (1).

23401452003133 is an equidigital number, since it uses as much as digits as its factorization.

23401452003133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 23401452003133 its reverse (33130025410432), we get a palindrome (56531477413565).

The spelling of 23401452003133 in words is "twenty-three trillion, four hundred one billion, four hundred fifty-two million, three thousand, one hundred thirty-three".