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2340421997 is a prime number
BaseRepresentation
bin1000101110000000…
…0000000101101101
320001002220202102012
42023200000011231
514243122000442
61024123211005
7111666154514
oct21340000555
96032822365
102340421997
11aa111a761
12553976a65
132b3b58ab4
14182b9167b
15da708582
hex8b80016d

2340421997 has 2 divisors, whose sum is σ = 2340421998. Its totient is φ = 2340421996.

The previous prime is 2340421991. The next prime is 2340421999. The reversal of 2340421997 is 7991240432.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1806165001 + 534256996 = 42499^2 + 23114^2 .

It is a cyclic number.

It is not a de Polignac number, because 2340421997 - 24 = 2340421981 is a prime.

Together with 2340421999, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2340421991) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1170210998 + 1170210999.

It is an arithmetic number, because the mean of its divisors is an integer number (1170210999).

Almost surely, 22340421997 is an apocalyptic number.

It is an amenable number.

2340421997 is a deficient number, since it is larger than the sum of its proper divisors (1).

2340421997 is an equidigital number, since it uses as much as digits as its factorization.

2340421997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108864, while the sum is 41.

The square root of 2340421997 is about 48377.9081503117. The cubic root of 2340421997 is about 1327.6941970561.

The spelling of 2340421997 in words is "two billion, three hundred forty million, four hundred twenty-one thousand, nine hundred ninety-seven".