Base | Representation |
---|---|
bin | 10101110100100110… |
… | …101000100110111101 |
3 | 2020110221210021212221 |
4 | 111310212220212331 |
5 | 340441331340331 |
6 | 14433014125341 |
7 | 1456434150055 |
oct | 256446504675 |
9 | 66427707787 |
10 | 23431121341 |
11 | 9a342912a1 |
12 | 465b050851 |
13 | 22954a8c54 |
14 | 11c3c74565 |
15 | 9220be711 |
hex | 5749a89bd |
23431121341 has 2 divisors, whose sum is σ = 23431121342. Its totient is φ = 23431121340.
The previous prime is 23431121317. The next prime is 23431121353. The reversal of 23431121341 is 14312113432.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17921176900 + 5509944441 = 133870^2 + 74229^2 .
It is a cyclic number.
It is not a de Polignac number, because 23431121341 - 215 = 23431088573 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23431121381) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11715560670 + 11715560671.
It is an arithmetic number, because the mean of its divisors is an integer number (11715560671).
Almost surely, 223431121341 is an apocalyptic number.
It is an amenable number.
23431121341 is a deficient number, since it is larger than the sum of its proper divisors (1).
23431121341 is an equidigital number, since it uses as much as digits as its factorization.
23431121341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1728, while the sum is 25.
Adding to 23431121341 its reverse (14312113432), we get a palindrome (37743234773).
The spelling of 23431121341 in words is "twenty-three billion, four hundred thirty-one million, one hundred twenty-one thousand, three hundred forty-one".
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