Base | Representation |
---|---|
bin | 1010101010100000001010… |
… | …10010001110101100110111 |
3 | 10002000212010100010200000121 |
4 | 11111100011102032230313 |
5 | 11033203322141213142 |
6 | 121513021143552411 |
7 | 4640151656652013 |
oct | 525200522165467 |
9 | 102025110120017 |
10 | 23450610101047 |
11 | 75213910560a8 |
12 | 2768a75a5b707 |
13 | 10114c971610c |
14 | 5b1030a9d543 |
15 | 2aa00e1cdc67 |
hex | 15540548eb37 |
23450610101047 has 2 divisors, whose sum is σ = 23450610101048. Its totient is φ = 23450610101046.
The previous prime is 23450610100991. The next prime is 23450610101069. The reversal of 23450610101047 is 74010101605432.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23450610101047 - 211 = 23450610098999 is a prime.
It is a super-2 number, since 2×234506101010472 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23450610101447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11725305050523 + 11725305050524.
It is an arithmetic number, because the mean of its divisors is an integer number (11725305050524).
Almost surely, 223450610101047 is an apocalyptic number.
23450610101047 is a deficient number, since it is larger than the sum of its proper divisors (1).
23450610101047 is an equidigital number, since it uses as much as digits as its factorization.
23450610101047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 34.
Adding to 23450610101047 its reverse (74010101605432), we get a palindrome (97460711706479).
The spelling of 23450610101047 in words is "twenty-three trillion, four hundred fifty billion, six hundred ten million, one hundred one thousand, forty-seven".
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