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23460433 is a prime number
BaseRepresentation
bin101100101111…
…1101001010001
31122010220122221
41121133221101
522001213213
62154501041
7403260523
oct131375121
948126587
1023460433
1112274197
127a34781
134b25519
143189a13
1520d638d
hex165fa51

23460433 has 2 divisors, whose sum is σ = 23460434. Its totient is φ = 23460432.

The previous prime is 23460431. The next prime is 23460443. The reversal of 23460433 is 33406432.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18045504 + 5414929 = 4248^2 + 2327^2 .

It is a cyclic number.

It is not a de Polignac number, because 23460433 - 21 = 23460431 is a prime.

Together with 23460431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 23460398 and 23460407.

It is not a weakly prime, because it can be changed into another prime (23460431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11730216 + 11730217.

It is an arithmetic number, because the mean of its divisors is an integer number (11730217).

Almost surely, 223460433 is an apocalyptic number.

It is an amenable number.

23460433 is a deficient number, since it is larger than the sum of its proper divisors (1).

23460433 is an equidigital number, since it uses as much as digits as its factorization.

23460433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 25.

The square root of 23460433 is about 4843.5971137162. The cubic root of 23460433 is about 286.2718697020.

Adding to 23460433 its reverse (33406432), we get a palindrome (56866865).

The spelling of 23460433 in words is "twenty-three million, four hundred sixty thousand, four hundred thirty-three".