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234831340 = 22553221539
BaseRepresentation
bin11011111111100…
…11110111101100
3121100212200001001
431333303313230
5440104100330
635145130044
75551014322
oct1577636754
9540780031
10234831340
11110613297
1266789924
1339861373
142328bd12
15159399ca
hexdff3dec

234831340 has 24 divisors (see below), whose sum is σ = 502452720. Its totient is φ = 92159808.

The previous prime is 234831323. The next prime is 234831347. The reversal of 234831340 is 43138432.

It is a junction number, because it is equal to n+sod(n) for n = 234831299 and 234831308.

It is not an unprimeable number, because it can be changed into a prime (234831347) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 109710 + ... + 111829.

It is an arithmetic number, because the mean of its divisors is an integer number (20935530).

Almost surely, 2234831340 is an apocalyptic number.

234831340 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

234831340 is an abundant number, since it is smaller than the sum of its proper divisors (267621380).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

234831340 is a wasteful number, since it uses less digits than its factorization.

234831340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 221601 (or 221599 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 28.

The square root of 234831340 is about 15324.2076467268. The cubic root of 234831340 is about 616.9529124789.

Adding to 234831340 its reverse (43138432), we get a palindrome (277969772).

The spelling of 234831340 in words is "two hundred thirty-four million, eight hundred thirty-one thousand, three hundred forty".

Divisors: 1 2 4 5 10 20 53 106 212 265 530 1060 221539 443078 886156 1107695 2215390 4430780 11741567 23483134 46966268 58707835 117415670 234831340