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2381147 is a prime number
BaseRepresentation
bin1001000101010101011011
311110222022122
421011111123
51102144042
6123011455
726145056
oct11052533
94428278
102381147
111386a9a
12969b8b
13654a82
1445da9d
153207d2
hex24555b

2381147 has 2 divisors, whose sum is σ = 2381148. Its totient is φ = 2381146.

The previous prime is 2381143. The next prime is 2381149. The reversal of 2381147 is 7411832.

2381147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2381147 - 22 = 2381143 is a prime.

It is a super-2 number, since 2×23811472 = 11339722071218, which contains 22 as substring.

Together with 2381149, it forms a pair of twin primes.

It is a Chen prime.

It is a plaindrome in base 16.

It is not a weakly prime, because it can be changed into another prime (2381143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1190573 + 1190574.

It is an arithmetic number, because the mean of its divisors is an integer number (1190574).

22381147 is an apocalyptic number.

2381147 is a deficient number, since it is larger than the sum of its proper divisors (1).

2381147 is an equidigital number, since it uses as much as digits as its factorization.

2381147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1344, while the sum is 26.

The square root of 2381147 is about 1543.0965621114. The cubic root of 2381147 is about 133.5350896927.

Adding to 2381147 its reverse (7411832), we get a palindrome (9792979).

The spelling of 2381147 in words is "two million, three hundred eighty-one thousand, one hundred forty-seven".