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240110135413 is a prime number
BaseRepresentation
bin1101111110011110101…
…1011110100001110101
3211221202200120200101021
43133213223132201311
512413221143313123
6302145521301141
723230103322211
oct3374753364165
9757680520337
10240110135413
1192914a03645
123a6504947b1
1319847153605
14b89b15b941
1563a4963c5d
hex37e7ade875

240110135413 has 2 divisors, whose sum is σ = 240110135414. Its totient is φ = 240110135412.

The previous prime is 240110135381. The next prime is 240110135417. The reversal of 240110135413 is 314531011042.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 186245759844 + 53864375569 = 431562^2 + 232087^2 .

It is a cyclic number.

It is not a de Polignac number, because 240110135413 - 25 = 240110135381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (240110135417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120055067706 + 120055067707.

It is an arithmetic number, because the mean of its divisors is an integer number (120055067707).

Almost surely, 2240110135413 is an apocalyptic number.

It is an amenable number.

240110135413 is a deficient number, since it is larger than the sum of its proper divisors (1).

240110135413 is an equidigital number, since it uses as much as digits as its factorization.

240110135413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 240110135413 its reverse (314531011042), we get a palindrome (554641146455).

The spelling of 240110135413 in words is "two hundred forty billion, one hundred ten million, one hundred thirty-five thousand, four hundred thirteen".