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24011131131313 is a prime number
BaseRepresentation
bin1010111010110100001101…
…11100010001010110110001
310011000102221000100021011121
411131122012330101112301
511121344244032200223
6123022321130542241
75025514133052634
oct535320674212661
9104012830307147
1024011131131313
117718077611387
122839627297981
13105231722a4b1
145d0205a43c1b
152b98b818415d
hex15d686f115b1

24011131131313 has 2 divisors, whose sum is σ = 24011131131314. Its totient is φ = 24011131131312.

The previous prime is 24011131131311. The next prime is 24011131131343. The reversal of 24011131131313 is 31313113111042.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22946092683264 + 1065038448049 = 4790208^2 + 1032007^2 .

It is a cyclic number.

It is not a de Polignac number, because 24011131131313 - 21 = 24011131131311 is a prime.

Together with 24011131131311, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (24011131131311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12005565565656 + 12005565565657.

It is an arithmetic number, because the mean of its divisors is an integer number (12005565565657).

Almost surely, 224011131131313 is an apocalyptic number.

It is an amenable number.

24011131131313 is a deficient number, since it is larger than the sum of its proper divisors (1).

24011131131313 is an equidigital number, since it uses as much as digits as its factorization.

24011131131313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 24011131131313 its reverse (31313113111042), we get a palindrome (55324244242355).

The spelling of 24011131131313 in words is "twenty-four trillion, eleven billion, one hundred thirty-one million, one hundred thirty-one thousand, three hundred thirteen".