Base | Representation |
---|---|
bin | 1010111010111000000101… |
… | …00000000010001101011111 |
3 | 10011000122021111000012010221 |
4 | 11131130002200002031133 |
5 | 11121413020222312111 |
6 | 123023302541542211 |
7 | 5025616404042112 |
oct | 535340240021537 |
9 | 104018244005127 |
10 | 24013204104031 |
11 | 7718a4076a47a |
12 | 2839b05574967 |
13 | 105258784447c |
14 | 5d0361096579 |
15 | 2b998a15d371 |
hex | 15d70280235f |
24013204104031 has 2 divisors, whose sum is σ = 24013204104032. Its totient is φ = 24013204104030.
The previous prime is 24013204104007. The next prime is 24013204104049. The reversal of 24013204104031 is 13040140231042.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 24013204104031 - 223 = 24013195715423 is a prime.
It is a super-2 number, since 2×240132041040312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 24013204103987 and 24013204104005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (24013204104061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12006602052015 + 12006602052016.
It is an arithmetic number, because the mean of its divisors is an integer number (12006602052016).
Almost surely, 224013204104031 is an apocalyptic number.
24013204104031 is a deficient number, since it is larger than the sum of its proper divisors (1).
24013204104031 is an equidigital number, since it uses as much as digits as its factorization.
24013204104031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 24013204104031 its reverse (13040140231042), we get a palindrome (37053344335073).
The spelling of 24013204104031 in words is "twenty-four trillion, thirteen billion, two hundred four million, one hundred four thousand, thirty-one".
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