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241221314025359 is a prime number
BaseRepresentation
bin110110110110001110110110…
…101111000001011110001111
31011122002112101010100212000222
4312312032312233001132033
5223104132222342302414
62213011313011541555
7101544444014325113
oct6666166657013617
91148075333325028
10241221314025359
116a9514261601a8
122307a381bba8bb
13a47a0c2b24a65
14437d261241743
151cd4abec7368e
hexdb63b6bc178f

241221314025359 has 2 divisors, whose sum is σ = 241221314025360. Its totient is φ = 241221314025358.

The previous prime is 241221314025331. The next prime is 241221314025361. The reversal of 241221314025359 is 953520413122142.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 241221314025359 - 220 = 241221312976783 is a prime.

It is a super-3 number, since 3×2412213140253593 (a number of 44 digits) contains 333 as substring.

Together with 241221314025361, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (241221314325359) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120610657012679 + 120610657012680.

It is an arithmetic number, because the mean of its divisors is an integer number (120610657012680).

Almost surely, 2241221314025359 is an apocalyptic number.

241221314025359 is a deficient number, since it is larger than the sum of its proper divisors (1).

241221314025359 is an equidigital number, since it uses as much as digits as its factorization.

241221314025359 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 518400, while the sum is 44.

The spelling of 241221314025359 in words is "two hundred forty-one trillion, two hundred twenty-one billion, three hundred fourteen million, twenty-five thousand, three hundred fifty-nine".