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241221504972509 is a prime number
BaseRepresentation
bin110110110110001111000010…
…000111011011011011011101
31011122002112212102122222021122
4312312033002013123123131
5223104133120233110014
62213011343552340325
7101544451523336255
oct6666170207333335
91148075772588248
10241221504972509
116a951513a1a666
122307a415b446a5
13a47a12355c639
14437d27c748965
151cd4ad18e058e
hexdb63c21db6dd

241221504972509 has 2 divisors, whose sum is σ = 241221504972510. Its totient is φ = 241221504972508.

The previous prime is 241221504972439. The next prime is 241221504972521. The reversal of 241221504972509 is 905279405122142.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 234415390996900 + 6806113975609 = 15310630^2 + 2608853^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-241221504972509 is a prime.

It is a super-3 number, since 3×2412215049725093 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (241221504902509) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120610752486254 + 120610752486255.

It is an arithmetic number, because the mean of its divisors is an integer number (120610752486255).

Almost surely, 2241221504972509 is an apocalyptic number.

It is an amenable number.

241221504972509 is a deficient number, since it is larger than the sum of its proper divisors (1).

241221504972509 is an equidigital number, since it uses as much as digits as its factorization.

241221504972509 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3628800, while the sum is 53.

The spelling of 241221504972509 in words is "two hundred forty-one trillion, two hundred twenty-one billion, five hundred four million, nine hundred seventy-two thousand, five hundred nine".