Base | Representation |
---|---|
bin | 110110110110100000100011… |
… | …111001110000011111001111 |
3 | 1011122011100110001200000200102 |
4 | 312312200203321300133033 |
5 | 223104440141302100403 |
6 | 2213024135304121315 |
7 | 101546016103500404 |
oct | 6666404371603717 |
9 | 1148140401600612 |
10 | 241240325425103 |
11 | 6a9594a1642214 |
12 | 23081ba8a6623b |
13 | a47bb32754214 |
14 | 43801461062ab |
15 | 1cd5333d10b88 |
hex | db6823e707cf |
241240325425103 has 2 divisors, whose sum is σ = 241240325425104. Its totient is φ = 241240325425102.
The previous prime is 241240325425069. The next prime is 241240325425129. The reversal of 241240325425103 is 301524523042142.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 241240325425103 - 224 = 241240308647887 is a prime.
It is a super-2 number, since 2×2412403254251032 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (241240325425153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120620162712551 + 120620162712552.
It is an arithmetic number, because the mean of its divisors is an integer number (120620162712552).
Almost surely, 2241240325425103 is an apocalyptic number.
241240325425103 is a deficient number, since it is larger than the sum of its proper divisors (1).
241240325425103 is an equidigital number, since it uses as much as digits as its factorization.
241240325425103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 230400, while the sum is 38.
Adding to 241240325425103 its reverse (301524523042142), we get a palindrome (542764848467245).
The spelling of 241240325425103 in words is "two hundred forty-one trillion, two hundred forty billion, three hundred twenty-five million, four hundred twenty-five thousand, one hundred three".
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