Base | Representation |
---|---|
bin | 110110110110101101100010… |
… | …000011010000011101110111 |
3 | 1011122012200101200212101002102 |
4 | 312312231202003100131313 |
5 | 223110202202232122123 |
6 | 2213034401312332315 |
7 | 101550021202121543 |
oct | 6666554203203567 |
9 | 1148180350771072 |
10 | 241254253004663 |
11 | 6a964399376948 |
12 | 2308483524409b |
13 | a480242057962 |
14 | 4380aa7b2aa23 |
15 | 1cd589b8db028 |
hex | db6b620d0777 |
241254253004663 has 2 divisors, whose sum is σ = 241254253004664. Its totient is φ = 241254253004662.
The previous prime is 241254253004659. The next prime is 241254253004669. The reversal of 241254253004663 is 366400352452142.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 241254253004663 - 22 = 241254253004659 is a prime.
It is a super-2 number, since 2×2412542530046632 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (241254253004669) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120627126502331 + 120627126502332.
It is an arithmetic number, because the mean of its divisors is an integer number (120627126502332).
Almost surely, 2241254253004663 is an apocalyptic number.
241254253004663 is a deficient number, since it is larger than the sum of its proper divisors (1).
241254253004663 is an equidigital number, since it uses as much as digits as its factorization.
241254253004663 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4147200, while the sum is 47.
The spelling of 241254253004663 in words is "two hundred forty-one trillion, two hundred fifty-four billion, two hundred fifty-three million, four thousand, six hundred sixty-three".
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