Base | Representation |
---|---|
bin | 110110110111100011100110… |
… | …001111010101111011011011 |
3 | 1011122102020020110120120100221 |
4 | 312313203212033111323123 |
5 | 223112130100131340443 |
6 | 2213121202003340511 |
7 | 101554144611620143 |
oct | 6667434617257333 |
9 | 1148366213516327 |
10 | 241312305340123 |
11 | 6a986a79402796 |
12 | 23093b36981737 |
13 | a485864132c04 |
14 | 4383813a69923 |
15 | 1cd7148167eed |
hex | db78e63d5edb |
241312305340123 has 2 divisors, whose sum is σ = 241312305340124. Its totient is φ = 241312305340122.
The previous prime is 241312305340121. The next prime is 241312305340153. The reversal of 241312305340123 is 321043503213142.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 241312305340123 - 21 = 241312305340121 is a prime.
Together with 241312305340121, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (241312305340121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120656152670061 + 120656152670062.
It is an arithmetic number, because the mean of its divisors is an integer number (120656152670062).
Almost surely, 2241312305340123 is an apocalyptic number.
241312305340123 is a deficient number, since it is larger than the sum of its proper divisors (1).
241312305340123 is an equidigital number, since it uses as much as digits as its factorization.
241312305340123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 241312305340123 its reverse (321043503213142), we get a palindrome (562355808553265).
The spelling of 241312305340123 in words is "two hundred forty-one trillion, three hundred twelve billion, three hundred five million, three hundred forty thousand, one hundred twenty-three".
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