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2413402211149 is a prime number
BaseRepresentation
bin100011000111101001111…
…110110100001101001101
322112201102011001002101121
4203013221332310031031
5304020121431224044
65044411321040541
7336235233214666
oct43075176641515
98481364032347
102413402211149
118505776a3846
1232b897626151
131467766ab267
1484b4899a36d
1542ba12c6984
hex231e9fb434d

2413402211149 has 2 divisors, whose sum is σ = 2413402211150. Its totient is φ = 2413402211148.

The previous prime is 2413402211063. The next prime is 2413402211173. The reversal of 2413402211149 is 9411122043142.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1680606289924 + 732795921225 = 1296382^2 + 856035^2 .

It is a cyclic number.

It is not a de Polignac number, because 2413402211149 - 217 = 2413402080077 is a prime.

It is a super-3 number, since 3×24134022111493 (a number of 38 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2413402211849) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1206701105574 + 1206701105575.

It is an arithmetic number, because the mean of its divisors is an integer number (1206701105575).

Almost surely, 22413402211149 is an apocalyptic number.

It is an amenable number.

2413402211149 is a deficient number, since it is larger than the sum of its proper divisors (1).

2413402211149 is an equidigital number, since it uses as much as digits as its factorization.

2413402211149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 34.

The spelling of 2413402211149 in words is "two trillion, four hundred thirteen billion, four hundred two million, two hundred eleven thousand, one hundred forty-nine".