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2413440123151 is a prime number
BaseRepresentation
bin100011000111101100001…
…111011100000100001111
322112201111210101012212211
4203013230033130010033
5304020211132420101
65044415153411251
7336236203365421
oct43075417340417
98481453335784
102413440123151
11850597038682
1232b8a8269b27
131467814c35b5
1484b4da28811
1542ba47b4c51
hex231ec3dc10f

2413440123151 has 2 divisors, whose sum is σ = 2413440123152. Its totient is φ = 2413440123150.

The previous prime is 2413440123089. The next prime is 2413440123197. The reversal of 2413440123151 is 1513210443142.

It is a happy number.

2413440123151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2413440123151 - 217 = 2413439992079 is a prime.

It is a super-2 number, since 2×24134401231512 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2413440123251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1206720061575 + 1206720061576.

It is an arithmetic number, because the mean of its divisors is an integer number (1206720061576).

Almost surely, 22413440123151 is an apocalyptic number.

2413440123151 is a deficient number, since it is larger than the sum of its proper divisors (1).

2413440123151 is an equidigital number, since it uses as much as digits as its factorization.

2413440123151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 2413440123151 its reverse (1513210443142), we get a palindrome (3926650566293).

The spelling of 2413440123151 in words is "two trillion, four hundred thirteen billion, four hundred forty million, one hundred twenty-three thousand, one hundred fifty-one".