Base | Representation |
---|---|
bin | 100011000111101100001… |
… | …111011100000100001111 |
3 | 22112201111210101012212211 |
4 | 203013230033130010033 |
5 | 304020211132420101 |
6 | 5044415153411251 |
7 | 336236203365421 |
oct | 43075417340417 |
9 | 8481453335784 |
10 | 2413440123151 |
11 | 850597038682 |
12 | 32b8a8269b27 |
13 | 1467814c35b5 |
14 | 84b4da28811 |
15 | 42ba47b4c51 |
hex | 231ec3dc10f |
2413440123151 has 2 divisors, whose sum is σ = 2413440123152. Its totient is φ = 2413440123150.
The previous prime is 2413440123089. The next prime is 2413440123197. The reversal of 2413440123151 is 1513210443142.
It is a happy number.
2413440123151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2413440123151 - 217 = 2413439992079 is a prime.
It is a super-2 number, since 2×24134401231512 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2413440123251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1206720061575 + 1206720061576.
It is an arithmetic number, because the mean of its divisors is an integer number (1206720061576).
Almost surely, 22413440123151 is an apocalyptic number.
2413440123151 is a deficient number, since it is larger than the sum of its proper divisors (1).
2413440123151 is an equidigital number, since it uses as much as digits as its factorization.
2413440123151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 2413440123151 its reverse (1513210443142), we get a palindrome (3926650566293).
The spelling of 2413440123151 in words is "two trillion, four hundred thirteen billion, four hundred forty million, one hundred twenty-three thousand, one hundred fifty-one".
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