Base | Representation |
---|---|
bin | 1010111110011001110101… |
… | …00110001101001001110111 |
3 | 10011110020010010121121021212 |
4 | 11133030322212031021313 |
5 | 11130404230002030403 |
6 | 123155105311232035 |
7 | 5040440016003644 |
oct | 537147246151167 |
9 | 104406103547255 |
10 | 24134404330103 |
11 | 7765386075171 |
12 | 28594ab21861b |
13 | 1060b315a1b82 |
14 | 5d617b98adcb |
15 | 2bcbd06964d8 |
hex | 15f33a98d277 |
24134404330103 has 2 divisors, whose sum is σ = 24134404330104. Its totient is φ = 24134404330102.
The previous prime is 24134404330061. The next prime is 24134404330121. The reversal of 24134404330103 is 30103340443142.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 24134404330103 - 216 = 24134404264567 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 24134404330103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (24134404330193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12067202165051 + 12067202165052.
It is an arithmetic number, because the mean of its divisors is an integer number (12067202165052).
Almost surely, 224134404330103 is an apocalyptic number.
24134404330103 is a deficient number, since it is larger than the sum of its proper divisors (1).
24134404330103 is an equidigital number, since it uses as much as digits as its factorization.
24134404330103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 24134404330103 its reverse (30103340443142), we get a palindrome (54237744773245).
The spelling of 24134404330103 in words is "twenty-four trillion, one hundred thirty-four billion, four hundred four million, three hundred thirty thousand, one hundred three".
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