Base | Representation |
---|---|
bin | 110110111000111001000001… |
… | …101100111101100010100111 |
3 | 1011122202000000012111122011011 |
4 | 312320321001230331202213 |
5 | 223120130430220110143 |
6 | 2213231252102123051 |
7 | 101563603002604363 |
oct | 6670710154754247 |
9 | 1148660005448134 |
10 | 241404034144423 |
11 | 6aa1196a980067 |
12 | 230a9876720487 |
13 | a4913c21783c7 |
14 | 43880363ca2a3 |
15 | 1cd9716187e9d |
hex | db8e41b3d8a7 |
241404034144423 has 2 divisors, whose sum is σ = 241404034144424. Its totient is φ = 241404034144422.
The previous prime is 241404034144409. The next prime is 241404034144463. The reversal of 241404034144423 is 324441430404142.
It is an a-pointer prime, because the next prime (241404034144463) can be obtained adding 241404034144423 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 241404034144423 - 213 = 241404034136231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (241404034144463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120702017072211 + 120702017072212.
It is an arithmetic number, because the mean of its divisors is an integer number (120702017072212).
Almost surely, 2241404034144423 is an apocalyptic number.
241404034144423 is a deficient number, since it is larger than the sum of its proper divisors (1).
241404034144423 is an equidigital number, since it uses as much as digits as its factorization.
241404034144423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 589824, while the sum is 40.
Adding to 241404034144423 its reverse (324441430404142), we get a palindrome (565845464548565).
The spelling of 241404034144423 in words is "two hundred forty-one trillion, four hundred four billion, thirty-four million, one hundred forty-four thousand, four hundred twenty-three".
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