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24142423012031 is a prime number
BaseRepresentation
bin1010111110101000110001…
…00011000011001010111111
310011110222210222011211222102
411133110120203003022333
511131022140242341111
6123202513115335315
75041142514453242
oct537243043031277
9104428728154872
1024142423012031
117768820442625
12285ab6875153b
13106180b95648c
145d66dc919259
152bceee63213b
hex15f5188c32bf

24142423012031 has 2 divisors, whose sum is σ = 24142423012032. Its totient is φ = 24142423012030.

The previous prime is 24142423012021. The next prime is 24142423012033. The reversal of 24142423012031 is 13021032424142.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 24142423012031 - 238 = 23867545105087 is a prime.

It is a super-2 number, since 2×241424230120312 (a number of 28 digits) contains 22 as substring.

Together with 24142423012033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 24142423011985 and 24142423012003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (24142423012033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12071211506015 + 12071211506016.

It is an arithmetic number, because the mean of its divisors is an integer number (12071211506016).

Almost surely, 224142423012031 is an apocalyptic number.

24142423012031 is a deficient number, since it is larger than the sum of its proper divisors (1).

24142423012031 is an equidigital number, since it uses as much as digits as its factorization.

24142423012031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 24142423012031 its reverse (13021032424142), we get a palindrome (37163455436173).

The spelling of 24142423012031 in words is "twenty-four trillion, one hundred forty-two billion, four hundred twenty-three million, twelve thousand, thirty-one".