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241424716441133 is a prime number
BaseRepresentation
bin110110111001001100010010…
…011101101010011000101101
31011122210222101120220011112102
4312321030102131222120231
5223121000304402104013
62213244552243344445
7101565234351330461
oct6671142235523055
91148728346804472
10241424716441133
116aa1a713557765
12230b1889082125
13a49333a0044b4
14438903915c4a1
151cda026c7ad58
hexdb931276a62d

241424716441133 has 2 divisors, whose sum is σ = 241424716441134. Its totient is φ = 241424716441132.

The previous prime is 241424716441127. The next prime is 241424716441177. The reversal of 241424716441133 is 331144617424142.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 227943504448804 + 13481211992329 = 15097798^2 + 3671677^2 .

It is a cyclic number.

It is not a de Polignac number, because 241424716441133 - 28 = 241424716440877 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (241424716441333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120712358220566 + 120712358220567.

It is an arithmetic number, because the mean of its divisors is an integer number (120712358220567).

Almost surely, 2241424716441133 is an apocalyptic number.

It is an amenable number.

241424716441133 is a deficient number, since it is larger than the sum of its proper divisors (1).

241424716441133 is an equidigital number, since it uses as much as digits as its factorization.

241424716441133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1548288, while the sum is 47.

The spelling of 241424716441133 in words is "two hundred forty-one trillion, four hundred twenty-four billion, seven hundred sixteen million, four hundred forty-one thousand, one hundred thirty-three".