Base | Representation |
---|---|
bin | 100011001000100000110… |
… | …011111101001101000101 |
3 | 22112210210020222212011121 |
4 | 203020200303331031011 |
5 | 304024012430030201 |
6 | 5045042501433541 |
7 | 336300103225432 |
oct | 43104063751505 |
9 | 8483706885147 |
10 | 2414322111301 |
11 | 8509a9988401 |
12 | 32bab370b8b1 |
13 | 146892151789 |
14 | 84bd4c16b89 |
15 | 42c06e349a1 |
hex | 23220cfd345 |
2414322111301 has 2 divisors, whose sum is σ = 2414322111302. Its totient is φ = 2414322111300.
The previous prime is 2414322111293. The next prime is 2414322111307. The reversal of 2414322111301 is 1031112234142.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2343379256100 + 70942855201 = 1530810^2 + 266351^2 .
It is a cyclic number.
It is not a de Polignac number, because 2414322111301 - 23 = 2414322111293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2414322111307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1207161055650 + 1207161055651.
It is an arithmetic number, because the mean of its divisors is an integer number (1207161055651).
Almost surely, 22414322111301 is an apocalyptic number.
It is an amenable number.
2414322111301 is a deficient number, since it is larger than the sum of its proper divisors (1).
2414322111301 is an equidigital number, since it uses as much as digits as its factorization.
2414322111301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 2414322111301 its reverse (1031112234142), we get a palindrome (3445434345443).
The spelling of 2414322111301 in words is "two trillion, four hundred fourteen billion, three hundred twenty-two million, one hundred eleven thousand, three hundred one".
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