Base | Representation |
---|---|
bin | 110110111010101111011000… |
… | …111101111101111011001111 |
3 | 1011200012011001110021112022201 |
4 | 312322233120331331323033 |
5 | 223124221221224414042 |
6 | 2213405511214022331 |
7 | 101606022314635351 |
oct | 6672573075757317 |
9 | 1150164043245281 |
10 | 241531126013647 |
11 | 6aa60858a27528 |
12 | 2310a4254a79a7 |
13 | a4a03976c33a2 |
14 | 43902515650d1 |
15 | 1cdcba3a531b7 |
hex | dbabd8f7decf |
241531126013647 has 2 divisors, whose sum is σ = 241531126013648. Its totient is φ = 241531126013646.
The previous prime is 241531126013629. The next prime is 241531126013659. The reversal of 241531126013647 is 746310621135142.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-241531126013647 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 241531126013597 and 241531126013606.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (241531126016647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120765563006823 + 120765563006824.
It is an arithmetic number, because the mean of its divisors is an integer number (120765563006824).
Almost surely, 2241531126013647 is an apocalyptic number.
241531126013647 is a deficient number, since it is larger than the sum of its proper divisors (1).
241531126013647 is an equidigital number, since it uses as much as digits as its factorization.
241531126013647 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 725760, while the sum is 46.
Adding to 241531126013647 its reverse (746310621135142), we get a palindrome (987841747148789).
The spelling of 241531126013647 in words is "two hundred forty-one trillion, five hundred thirty-one billion, one hundred twenty-six million, thirteen thousand, six hundred forty-seven".
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