Base | Representation |
---|---|
bin | 100011010000111101111… |
… | …110010101000000100101 |
3 | 22120200020000002122021121 |
4 | 203100331332111000211 |
5 | 304201111213212401 |
6 | 5053143432213541 |
7 | 340041100131331 |
oct | 43207576250045 |
9 | 8520200078247 |
10 | 2423401304101 |
11 | 854838949328 |
12 | 33180823a2b1 |
13 | 1476ab13b8cb |
14 | 854169647c1 |
15 | 43089055ca1 |
hex | 2343df95025 |
2423401304101 has 2 divisors, whose sum is σ = 2423401304102. Its totient is φ = 2423401304100.
The previous prime is 2423401304081. The next prime is 2423401304179. The reversal of 2423401304101 is 1014031043242.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2418942537025 + 4458767076 = 1555295^2 + 66774^2 .
It is a cyclic number.
It is not a de Polignac number, because 2423401304101 - 211 = 2423401302053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2423401304201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1211700652050 + 1211700652051.
It is an arithmetic number, because the mean of its divisors is an integer number (1211700652051).
Almost surely, 22423401304101 is an apocalyptic number.
It is an amenable number.
2423401304101 is a deficient number, since it is larger than the sum of its proper divisors (1).
2423401304101 is an equidigital number, since it uses as much as digits as its factorization.
2423401304101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2423401304101 its reverse (1014031043242), we get a palindrome (3437432347343).
The spelling of 2423401304101 in words is "two trillion, four hundred twenty-three billion, four hundred one million, three hundred four thousand, one hundred one".
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