Base | Representation |
---|---|
bin | 110111000111100100000101… |
… | …000101001110100011011111 |
3 | 1011210022101121101100020101222 |
4 | 313013210011011032203133 |
5 | 223233140430102104301 |
6 | 2215322404500123555 |
7 | 102026466425500316 |
oct | 6707440505164337 |
9 | 1153271541306358 |
10 | 242412334409951 |
11 | 70270548109332 |
12 | 232311743965bb |
13 | a535500c48964 |
14 | 43c0b68d3d27d |
15 | 1d05a7b45c31b |
hex | dc790514e8df |
242412334409951 has 2 divisors, whose sum is σ = 242412334409952. Its totient is φ = 242412334409950.
The previous prime is 242412334409923. The next prime is 242412334410187. The reversal of 242412334409951 is 159904433214242.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 242412334409951 - 210 = 242412334408927 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 242412334409893 and 242412334409902.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (242412334402951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121206167204975 + 121206167204976.
It is an arithmetic number, because the mean of its divisors is an integer number (121206167204976).
Almost surely, 2242412334409951 is an apocalyptic number.
242412334409951 is a deficient number, since it is larger than the sum of its proper divisors (1).
242412334409951 is an equidigital number, since it uses as much as digits as its factorization.
242412334409951 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7464960, while the sum is 53.
The spelling of 242412334409951 in words is "two hundred forty-two trillion, four hundred twelve billion, three hundred thirty-four million, four hundred nine thousand, nine hundred fifty-one".
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