Base | Representation |
---|---|
bin | 100011010001101101101… |
… | …101001100111110111011 |
3 | 22120202021210222100202012 |
4 | 203101231231030332323 |
5 | 304204231220334042 |
6 | 5053355120400135 |
7 | 340066663020032 |
oct | 43215555147673 |
9 | 8522253870665 |
10 | 2424202121147 |
11 | 855109997aa4 |
12 | 3319b047604b |
13 | 1477a8019651 |
14 | 85491063719 |
15 | 430d44dee82 |
hex | 2346db4cfbb |
2424202121147 has 2 divisors, whose sum is σ = 2424202121148. Its totient is φ = 2424202121146.
The previous prime is 2424202121087. The next prime is 2424202121149. The reversal of 2424202121147 is 7411212024242.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2424202121147 - 220 = 2424201072571 is a prime.
It is a super-2 number, since 2×24242021211472 (a number of 26 digits) contains 22 as substring.
Together with 2424202121149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2424202121149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1212101060573 + 1212101060574.
It is an arithmetic number, because the mean of its divisors is an integer number (1212101060574).
Almost surely, 22424202121147 is an apocalyptic number.
2424202121147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2424202121147 is an equidigital number, since it uses as much as digits as its factorization.
2424202121147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14336, while the sum is 32.
Adding to 2424202121147 its reverse (7411212024242), we get a palindrome (9835414145389).
The spelling of 2424202121147 in words is "two trillion, four hundred twenty-four billion, two hundred two million, one hundred twenty-one thousand, one hundred forty-seven".
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