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2430311131132 = 222955339378593
BaseRepresentation
bin100011010111011001110…
…101001110011111111100
322121100001120011020000021
4203113121311032133330
5304304234122144012
65100245225541524
7340404242524543
oct43273165163774
98540046136007
102430311131132
11857764303685
123330163448a4
1314823c861c61
14858b052b15a
15433409ac007
hex235d9d4e7fc

2430311131132 has 24 divisors (see below), whose sum is σ = 4399792311600. Its totient is φ = 1173229349376.

The previous prime is 2430311131121. The next prime is 2430311131139. The reversal of 2430311131132 is 2311311130342.

It is a junction number, because it is equal to n+sod(n) for n = 2430311131097 and 2430311131106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2430311131139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6230028 + ... + 6608620.

It is an arithmetic number, because the mean of its divisors is an integer number (183324679650).

Almost surely, 22430311131132 is an apocalyptic number.

It is an amenable number.

2430311131132 is a deficient number, since it is larger than the sum of its proper divisors (1969481180468).

2430311131132 is a wasteful number, since it uses less digits than its factorization.

2430311131132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 433965 (or 433963 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 2430311131132 its reverse (2311311130342), we get a palindrome (4741622261474).

The spelling of 2430311131132 in words is "two trillion, four hundred thirty billion, three hundred eleven million, one hundred thirty-one thousand, one hundred thirty-two".

Divisors: 1 2 4 29 58 116 55339 110678 221356 378593 757186 1514372 1604831 3209662 6419324 10979197 21958394 43916788 20950958027 41901916054 83803832108 607577782783 1215155565566 2430311131132