Base | Representation |
---|---|
bin | 1110001001101100100… |
… | …1001011011011001011 |
3 | 212020112112010122022112 |
4 | 3202123021023123023 |
5 | 12440402441340042 |
6 | 303404355412535 |
7 | 23364523524653 |
oct | 3423311133313 |
9 | 766475118275 |
10 | 243121043147 |
11 | 9411a544144 |
12 | 3b1508b414b |
13 | 19c06b86918 |
14 | baa4da3363 |
15 | 64cde5e982 |
hex | 389b24b6cb |
243121043147 has 2 divisors, whose sum is σ = 243121043148. Its totient is φ = 243121043146.
The previous prime is 243121043101. The next prime is 243121043149. The reversal of 243121043147 is 741340121342.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 243121043147 - 28 = 243121042891 is a prime.
Together with 243121043149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (243121043149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121560521573 + 121560521574.
It is an arithmetic number, because the mean of its divisors is an integer number (121560521574).
Almost surely, 2243121043147 is an apocalyptic number.
243121043147 is a deficient number, since it is larger than the sum of its proper divisors (1).
243121043147 is an equidigital number, since it uses as much as digits as its factorization.
243121043147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 243121043147 its reverse (741340121342), we get a palindrome (984461164489).
The spelling of 243121043147 in words is "two hundred forty-three billion, one hundred twenty-one million, forty-three thousand, one hundred forty-seven".
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