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243121300421 is a prime number
BaseRepresentation
bin1110001001101100101…
…0001010001111000101
3212020112112121201020012
43202123022022033011
512440403023103141
6303404405120005
723364525646016
oct3423312121705
9766475551205
10243121300421
119411a6aa46a
123b1509b9005
1319c06c46a5c
14baa502d00d
1564cdeb0ceb
hex389b28a3c5

243121300421 has 2 divisors, whose sum is σ = 243121300422. Its totient is φ = 243121300420.

The previous prime is 243121300403. The next prime is 243121300441. The reversal of 243121300421 is 124003121342.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 140666253025 + 102455047396 = 375055^2 + 320086^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-243121300421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (243121300441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121560650210 + 121560650211.

It is an arithmetic number, because the mean of its divisors is an integer number (121560650211).

Almost surely, 2243121300421 is an apocalyptic number.

It is an amenable number.

243121300421 is a deficient number, since it is larger than the sum of its proper divisors (1).

243121300421 is an equidigital number, since it uses as much as digits as its factorization.

243121300421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 243121300421 its reverse (124003121342), we get a palindrome (367124421763).

The spelling of 243121300421 in words is "two hundred forty-three billion, one hundred twenty-one million, three hundred thousand, four hundred twenty-one".