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243121300441 is a prime number
BaseRepresentation
bin1110001001101100101…
…0001010001111011001
3212020112112121201020221
43202123022022033121
512440403023103231
6303404405120041
723364525646045
oct3423312121731
9766475551227
10243121300441
119411a6aa488
123b1509b9021
1319c06c46a76
14baa502d025
1564cdeb0d11
hex389b28a3d9

243121300441 has 2 divisors, whose sum is σ = 243121300442. Its totient is φ = 243121300440.

The previous prime is 243121300421. The next prime is 243121300453. The reversal of 243121300441 is 144003121342.

243121300441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 174527595225 + 68593705216 = 417765^2 + 261904^2 .

It is a cyclic number.

It is not a de Polignac number, because 243121300441 - 211 = 243121298393 is a prime.

It is not a weakly prime, because it can be changed into another prime (243121300421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121560650220 + 121560650221.

It is an arithmetic number, because the mean of its divisors is an integer number (121560650221).

Almost surely, 2243121300441 is an apocalyptic number.

It is an amenable number.

243121300441 is a deficient number, since it is larger than the sum of its proper divisors (1).

243121300441 is an equidigital number, since it uses as much as digits as its factorization.

243121300441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 243121300441 its reverse (144003121342), we get a palindrome (387124421783).

The spelling of 243121300441 in words is "two hundred forty-three billion, one hundred twenty-one million, three hundred thousand, four hundred forty-one".