243125437 has 2 divisors, whose sum is σ = 243125438. Its totient is φ = 243125436.

The previous prime is 243125339. The next prime is 243125453. The reversal of 243125437 is 734521342.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 241522681 + 1602756 = 15541^2 + 1266^2 .

It is a cyclic number.

It is not a de Polignac number, because 243125437 - 2¹¹ = 243123389 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 243125399 and 243125408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (243125137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121562718 + 121562719.

It is an arithmetic number, because the mean of its divisors is an integer number (121562719).

Almost surely, 2^243125437 is an apocalyptic number.

It is an amenable number.

243125437 is a deficient number, since it is larger than the sum of its proper divisors (1).

243125437 is an equidigital number, since it uses as much as digits as its factorization.

243125437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 20160, while the sum is 31.

The square root of 243125437 is about 15592.4801426842. The cubic root of 243125437 is about 624.1325027146.

Adding to 243125437 its reverse (734521342), we get a palindrome (977646779).

The spelling of 243125437 in words is "two hundred forty-three million, one hundred twenty-five thousand, four hundred thirty-seven".