243354015131 has 2 divisors, whose sum is σ = 243354015132. Its totient is φ = 243354015130.

The previous prime is 243354015067. The next prime is 243354015133. The reversal of 243354015131 is 131510453342.

243354015131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 243354015131 - 2⁶ = 243354015067 is a prime.

It is a super-3 number, since 3×243354015131³ (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 243354015133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (243354015133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121677007565 + 121677007566.

It is an arithmetic number, because the mean of its divisors is an integer number (121677007566).

Almost surely, 2^243354015131 is an apocalyptic number.

243354015131 is a deficient number, since it is larger than the sum of its proper divisors (1).

243354015131 is an equidigital number, since it uses as much as digits as its factorization.

243354015131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 32.

Adding to 243354015131 its reverse (131510453342), we get a palindrome (374864468473).

The spelling of 243354015131 in words is "two hundred forty-three billion, three hundred fifty-four million, fifteen thousand, one hundred thirty-one".