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24341430437 is a prime number
BaseRepresentation
bin10110101010110111…
…001100000010100101
32022211101200210012122
4112222313030002211
5344322401233222
615103213155325
71521126513332
oct265267140245
968741623178
1024341430437
11a361114a65
124873a8bb45
1323abc71a9c
14126cb15989
15976e85a42
hex5aadcc0a5

24341430437 has 2 divisors, whose sum is σ = 24341430438. Its totient is φ = 24341430436.

The previous prime is 24341430419. The next prime is 24341430439. The reversal of 24341430437 is 73403414342.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15842249956 + 8499180481 = 125866^2 + 92191^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-24341430437 is a prime.

Together with 24341430439, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 24341430397 and 24341430406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (24341430439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12170715218 + 12170715219.

It is an arithmetic number, because the mean of its divisors is an integer number (12170715219).

Almost surely, 224341430437 is an apocalyptic number.

It is an amenable number.

24341430437 is a deficient number, since it is larger than the sum of its proper divisors (1).

24341430437 is an equidigital number, since it uses as much as digits as its factorization.

24341430437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96768, while the sum is 35.

Adding to 24341430437 its reverse (73403414342), we get a palindrome (97744844779).

The spelling of 24341430437 in words is "twenty-four billion, three hundred forty-one million, four hundred thirty thousand, four hundred thirty-seven".