243434202047 has 2 divisors, whose sum is σ = 243434202048. Its totient is φ = 243434202046.

The previous prime is 243434202023. The next prime is 243434202049. The reversal of 243434202047 is 740202434342.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-243434202047 is a prime.

It is a super-3 number, since 3×243434202047³ (a number of 35 digits) contains 333 as substring.

Together with 243434202049, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 243434201998 and 243434202016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (243434202049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121717101023 + 121717101024.

It is an arithmetic number, because the mean of its divisors is an integer number (121717101024).

Almost surely, 2^243434202047 is an apocalyptic number.

243434202047 is a deficient number, since it is larger than the sum of its proper divisors (1).

243434202047 is an equidigital number, since it uses as much as digits as its factorization.

243434202047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129024, while the sum is 35.

Adding to 243434202047 its reverse (740202434342), we get a palindrome (983636636389).

The spelling of 243434202047 in words is "two hundred forty-three billion, four hundred thirty-four million, two hundred two thousand, forty-seven".