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2434354555541 is a prime number
BaseRepresentation
bin100011011011001010110…
…101101010101010010101
322121201111100120110112212
4203123022311222222111
5304341024231234131
65102154350323205
7340606401211106
oct43331265525225
98551440513485
102434354555541
11859449757247
123339644b9505
13148735478a8c
1485b755463ad
15434ca95da2b
hex236cad6aa95

2434354555541 has 2 divisors, whose sum is σ = 2434354555542. Its totient is φ = 2434354555540.

The previous prime is 2434354555459. The next prime is 2434354555543. The reversal of 2434354555541 is 1455554534342.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2198906402641 + 235448152900 = 1482871^2 + 485230^2 .

It is a cyclic number.

It is not a de Polignac number, because 2434354555541 - 210 = 2434354554517 is a prime.

Together with 2434354555543, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2434354555541.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2434354555543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1217177277770 + 1217177277771.

It is an arithmetic number, because the mean of its divisors is an integer number (1217177277771).

Almost surely, 22434354555541 is an apocalyptic number.

It is an amenable number.

2434354555541 is a deficient number, since it is larger than the sum of its proper divisors (1).

2434354555541 is an equidigital number, since it uses as much as digits as its factorization.

2434354555541 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14400000, while the sum is 50.

The spelling of 2434354555541 in words is "two trillion, four hundred thirty-four billion, three hundred fifty-four million, five hundred fifty-five thousand, five hundred forty-one".