Base | Representation |
---|---|
bin | 1110001100111111011… |
… | …0011001101001100101 |
3 | 212022211011001012200110 |
4 | 3203033312121221211 |
5 | 12444210330010000 |
6 | 304032224403233 |
7 | 23425451640360 |
oct | 3431766315145 |
9 | 768734035613 |
10 | 244005313125 |
11 | 94533702282 |
12 | 3b358a76519 |
13 | 1a0181335b2 |
14 | bb4a5c70d7 |
15 | 65318d0850 |
hex | 38cfd99a65 |
244005313125 has 80 divisors (see below), whose sum is σ = 465963344000. Its totient is φ = 111223584000.
The previous prime is 244005313103. The next prime is 244005313151. The reversal of 244005313125 is 521313500442.
It is not a de Polignac number, because 244005313125 - 215 = 244005280357 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 244005313092 and 244005313101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 4553991 + ... + 4607259.
It is an arithmetic number, because the mean of its divisors is an integer number (5824541800).
Almost surely, 2244005313125 is an apocalyptic number.
244005313125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
244005313125 is a deficient number, since it is larger than the sum of its proper divisors (221958030875).
244005313125 is an equidigital number, since it uses as much as digits as its factorization.
244005313125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53648 (or 53633 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 244005313125 its reverse (521313500442), we get a palindrome (765318813567).
The spelling of 244005313125 in words is "two hundred forty-four billion, five million, three hundred thirteen thousand, one hundred twenty-five".
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