2441143320541 has 2 divisors, whose sum is σ = 2441143320542. Its totient is φ = 2441143320540.

The previous prime is 2441143320509. The next prime is 2441143320563. The reversal of 2441143320541 is 1450233411442.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2051741112100 + 389402208441 = 1432390^2 + 624021^2 .

It is a cyclic number.

It is not a de Polignac number, because 2441143320541 - 2⁵ = 2441143320509 is a prime.

It is a super-2 number, since 2×2441143320541² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2441143320497 and 2441143320506.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2441143330541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1220571660270 + 1220571660271.

It is an arithmetic number, because the mean of its divisors is an integer number (1220571660271).

Almost surely, 2^{2441143320541} is an apocalyptic number.

It is an amenable number.

2441143320541 is a deficient number, since it is larger than the sum of its proper divisors (1).

2441143320541 is an equidigital number, since it uses as much as digits as its factorization.

2441143320541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 46080, while the sum is 34.

Adding to 2441143320541 its reverse (1450233411442), we get a palindrome (3891376731983).

Subtracting from 2441143320541 its reverse (1450233411442), we obtain a palindrome (990909909099).

The spelling of 2441143320541 in words is "two trillion, four hundred forty-one billion, one hundred forty-three million, three hundred twenty thousand, five hundred forty-one".