Base | Representation |
---|---|
bin | 100011100011100000110… |
… | …011011110000101110011 |
3 | 22122120121200111021001112 |
4 | 203203200303132011303 |
5 | 310012401112404412 |
6 | 5110235325223535 |
7 | 341344400641151 |
oct | 43434063360563 |
9 | 8576550437045 |
10 | 2443313013107 |
11 | 862226553a8a |
12 | 335644701bab |
13 | 149532442445 |
14 | 863852263d1 |
15 | 43852181722 |
hex | 238e0cde173 |
2443313013107 has 2 divisors, whose sum is σ = 2443313013108. Its totient is φ = 2443313013106.
The previous prime is 2443313013101. The next prime is 2443313013139. The reversal of 2443313013107 is 7013103133442.
2443313013107 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an a-pointer prime, because the next prime (2443313013139) can be obtained adding 2443313013107 to its sum of digits (32).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2443313013107 - 216 = 2443312947571 is a prime.
It is not a weakly prime, because it can be changed into another prime (2443313013101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1221656506553 + 1221656506554.
It is an arithmetic number, because the mean of its divisors is an integer number (1221656506554).
Almost surely, 22443313013107 is an apocalyptic number.
2443313013107 is a deficient number, since it is larger than the sum of its proper divisors (1).
2443313013107 is an equidigital number, since it uses as much as digits as its factorization.
2443313013107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 32.
Adding to 2443313013107 its reverse (7013103133442), we get a palindrome (9456416146549).
The spelling of 2443313013107 in words is "two trillion, four hundred forty-three billion, three hundred thirteen million, thirteen thousand, one hundred seven".
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