2443313014111 has 2 divisors, whose sum is σ = 2443313014112. Its totient is φ = 2443313014110.

The previous prime is 2443313014027. The next prime is 2443313014193. The reversal of 2443313014111 is 1114103133442.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2443313014111 - 2⁷ = 2443313013983 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2443313014111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2443313012111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1221656507055 + 1221656507056.

It is an arithmetic number, because the mean of its divisors is an integer number (1221656507056).

Almost surely, 2^{2443313014111} is an apocalyptic number.

2443313014111 is a deficient number, since it is larger than the sum of its proper divisors (1).

2443313014111 is an equidigital number, since it uses as much as digits as its factorization.

2443313014111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 2443313014111 its reverse (1114103133442), we get a palindrome (3557416147553).

The spelling of 2443313014111 in words is "two trillion, four hundred forty-three billion, three hundred thirteen million, fourteen thousand, one hundred eleven".